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15x^2-75x=0
a = 15; b = -75; c = 0;
Δ = b2-4ac
Δ = -752-4·15·0
Δ = 5625
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{5625}=75$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-75)-75}{2*15}=\frac{0}{30} =0 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-75)+75}{2*15}=\frac{150}{30} =5 $
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